x^2+13x+19=0

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Solution for x^2+13x+19=0 equation:



x^2+13x+19=0
a = 1; b = 13; c = +19;
Δ = b2-4ac
Δ = 132-4·1·19
Δ = 93
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{93}}{2*1}=\frac{-13-\sqrt{93}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{93}}{2*1}=\frac{-13+\sqrt{93}}{2} $

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